我会假设这是某种兼容性问题。在 chrome 中一切正常,但在 Firefox 中<canvas>
根本不绘制任何东西。
function drawStage(stageNum) {
var cap = canvasArray.length; //keeps the canvasElements
var i;
var stageImages = images["stage" + stageNum];
var stageDimensions = imageDimensions["stage" + stageNum];
//console.log("Cap is: " + cap);
for (i = 0; i < cap; i++) {
var canvas = document.getElementById(canvasArray[i]);
var canvasContext = canvas.getContext("2d");
var image = document.getElementById(stageImages[i]);
canvasContext.clearRect(0, 0, 1280, 1280);
canvasContext.drawImage(image, stageDimensions[i][0], stageDimensions[i][1], stageDimensions[i][2], stageDimensions[i][3]);
//document.getElementById(zIndexes[i][0]).style["z-index"] = zIndexes[i][stageNum];
//console.log(document.getElementById(zIndexes[i][0]).id);
}
}
编辑: 这是我制作的“测试”代码示例的 dropbox 链接,简单得多,1 张图像、1 个画布、1 个 div、类似(几乎相同)的脚本,它仍然无法在 Firefox 中工作,但可以在 chrome 中工作。如果你能在那里解决问题,那么这也将得到解决。
更新:数组如下,根据请求,它们是不同元素/坐标的简单输入。不过我向你保证,阵列本身没有问题,在 chrome 中一切正常。函数中的 DrawImage() 方法导致了我要说的问题。(阵列下方的进一步解释)
images 是<img>
元素id 的(全局)数组。
var images = {
stage1: ["character1Base", "character2Base", "character3Base", "character4Base", "character5Base", "character6Base", "character3BotImg"],
stage2: ["character1Sit", "character2Base", "character3Base", "character4Base", "character5Base", "character6Base", "character3BotImg"],
stage3: ["character1Sit", "character2Drink", "character3Base", "character4Base", "character5Base", "character6Base", "character3BotImg"],
stage4: ["character1Sit", "character2Drink", "character3Base", "character4Base", "character5Base", "character6Doll", "character3BotImg"],
stage5: ["character1Sit", "character2Drink", "character3Eat", "character4Base", "character5Base", "character6Doll", "character3EatBot"],
stage6: ["character1Sit", "character2Stand", "character3Eat", "character4Base", "character5Base", "character6Doll", "character3EatBot"],
stage7: ["character1Sit", "character2Stand", "character3Eat", "character4Sit", "character5Base", "character6Doll", "character3EatBot"],
stage8: ["character1Sit", "character2Stand", "character3Eat", "character4Sit", "character5Sit", "character6Doll", "character3EatBot"],
stage9: ["character1Sit", "character2Eat", "character3Eat", "character4Sit", "character5Sit", "character6Doll", "character3EatBot"],
stage10: ["character1Drink", "character2Eat", "character3Eat", "character4Sit", "character5Sit", "character6Doll", "character3EatBot"]
};
imageDimensions 是井、尺寸、posX、posY、sizeX 和 sizeY 的(全局)数组。
var imageDimensions = {
stage1: [[0, 0, 233, 485], [0, 0, 153, 407], [20, 0, 220, 200], [0, 150, 505, 210], [0, 0, 315, 391], [0, 0, 480, 435], [1, 0, 220, 180]],
stage2: [[105, 35, 180, 440], [0, 0, 153, 407], [20, 0, 220, 200], [0, 150, 505, 210], [0, 0, 315, 391], [0, 0, 480, 435], [1, 0, 220, 180]],
stage3: [[105, 35, 180, 440], [0, 0, 153, 407], [20, 0, 220, 200], [0, 150, 505, 210], [0, 0, 315, 391], [0, 0, 480, 435], [1, 0, 220, 180]],
stage4: [[105, 35, 180, 440], [0, 0, 153, 407], [20, 0, 220, 200], [0, 150, 505, 210], [0, 0, 315, 391], [0, 0, 480, 435], [1, 0, 220, 180]],
stage5: [[105, 35, 180, 440], [0, 0, 153, 407], [3, 7, 226, 180], [0, 150, 505, 210], [0, 0, 315, 391], [0, 0, 480, 435], [1, 9, 220, 180]],
stage6: [[105, 35, 180, 440], [0, 0, 172, 490], [3, 7, 226, 180], [0, 150, 505, 210], [0, 0, 315, 391], [0, 0, 480, 435], [1, 9, 220, 180]],
stage7: [[105, 35, 180, 440], [0, 0, 172, 490], [3, 7, 226, 180], [70, 0, 341, 380], [0, 0, 315, 391], [0, 0, 480, 435], [1, 9, 220, 180]],
stage8: [[105, 35, 180, 440], [0, 0, 172, 490], [3, 7, 226, 180], [70, 0, 341, 380], [18, 72, 305, 422], [0, 0, 480, 435], [1, 9, 220, 180]],
stage9: [[105, 35, 180, 440], [0, 0, 173, 473], [3, 7, 226, 180], [70, 0, 341, 380], [18, 72, 305, 422], [0, 0, 480, 435], [1, 9, 220, 180]],
stage10: [[105, 32, 162, 440], [0, 0, 173, 473], [3, 7, 226, 180], [70, 0, 341, 380], [18, 72, 305, 422], [0, 0, 480, 435], [1, 9, 220, 180]]
};
说明:
该函数的目的是在屏幕上绘制不同的元素,属于这些元素的字符。它们是在画布中绘制的(稍后也会在画布中进行动画处理)。该stageNum
这是唯一参数的函数需要确定哪些会被吸引。
有谁知道问题是什么?(我已经阅读了一些类似的帖子,但所有帖子的问题都是鼠标位置的 layerX、layerY,但是我根本没有在这里使用 mouseover/mousein/mouseout,仍然没有绘制元素。