我有一组对象，我想知道搜索它的最佳方法。鉴于以下示例，我如何搜索name = "Joe"和age < 30？有什么 jQuery 可以帮助的，或者我必须自己暴力搜索吗？
var names = new Array();
var object = { name : "Joe", age:20, email: "joe@hotmail.com"};
names.push(object);
object = { name : "Mike", age:50, email: "mike@hotmail.com"};
names.push(object);
object = { name : "Joe", age:45, email: "mike@hotmail.com"};
names.push(object);
现代解决方案Array.prototype.filter()：
const found_names = names.filter(v => v.name === "Joe" && v.age < 30);
或者，如果您仍在使用 jQuery，则可以使用jQuery.grep()：
var found_names = $.grep(names, function(v) {
return v.name === "Joe" && v.age < 30;
});
您可以使用以下[].filter方法轻松完成此操作：
var filterednames = names.filter(function(obj) {
return (obj.name === "Joe") && (obj.age < 30);
});
您可以在此 MDN 页面上了解更多相关信息。
您可以利用jQuery.filter()函数从匹配元素的子集中返回元素。
var names = [
{ name : "Joe", age:20, email: "joe@hotmail.com"},
{ name : "Mike", age:50, email: "mike@hotmail.com"},
{ name : "Joe", age:45, email: "mike@hotmail.com"}
];
var filteredNames = $(names).filter(function( idx ) {
return names[idx].name === "Joe" && names[idx].age < 30;
});
$(filteredNames).each(function(){
$('#output').append(this.name);
});<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="output"/>var nameList = [
{name:'x', age:20, email:'x@email.com'},
{name:'y', age:60, email:'y@email.com'},
{name:'Joe', age:22, email:'joe@email.com'},
{name:'Abc', age:40, email:'abc@email.com'}
];
var filteredValue = nameList.filter(function (item) {
return item.name == "Joe" && item.age < 30;
});
//To See Output Result as Array
console.log(JSON.stringify(filteredValue));你可以简单地使用 javascript :)
对于那些想要使用任意键从对象数组中进行过滤的人：
function filterItems(items, searchVal) {
return items.filter((item) => Object.values(item).includes(searchVal));
}
let data = [
{ "name": "apple", "type": "fruit", "id": 123234 },
{ "name": "cat", "type": "animal", "id": 98989 },
{ "name": "something", "type": "other", "id": 656565 }]
console.log("Filtered by name: ", filterItems(data, "apple"));
console.log("Filtered by type: ", filterItems(data, "animal"));
console.log("Filtered by id: ", filterItems(data, 656565));从 JSON 对象数组中过滤：**