按 Enter React.js 时专注于下一个字段

IT技术 javascript reactjs
2021-05-18 15:07:09

当我使用 React.js 在输入中单击 Enter 时,我想找到一种专注于下一个字段的方法

  @autobind
  handleKeyPress(event){
    if(event.key === 'Enter'){
      this.refs.email.focus();
    }
  }

  @autobind
  handleKeyPressEmail(event){
    if(event.key === 'Enter'){
      this.refs.zip_code.focus();
    }
  }

        <input
          onKeyPress={this.handleKeyPress}
          ref = 'name'
        />

        <input
          onKeyPress={this.handleKeyPressEmail}
          ref = 'email'
        />

        <input
          ref = 'zip_code'
        />

这是迄今为止我发现的最好的方法,但是我不想在每次我希望发生这种情况时通过创建一个函数来重复自己。有没有更好更干净的方法来实现这一点?

4个回答

如果<form>存在:

function handleEnter(event) {
  if (event.keyCode === 13) {
    const form = event.target.form;
    const index = Array.prototype.indexOf.call(form, event.target);
    form.elements[index + 1].focus();
    event.preventDefault();
  }
}
...
<form>
  <input onKeyDown={handleEnter} />
  <input onKeyDown={handleEnter} />
  <input />
</form>

代码笔

没有<form>

function useFocusNext() {
  const controls = useRef([]);

  const handler = (event) => {
    if (event.keyCode === 13) {
      // Required if the controls can be reordered
      controls.current = controls.current
        .filter((control) => document.body.contains(control))
        .sort((a, b) =>
          a.compareDocumentPosition(b) & Node.DOCUMENT_POSITION_FOLLOWING
            ? -1 : 1
        );

      const index = controls.current.indexOf(event.target);
      const next = controls.current[index + 1];
      next && next.focus();

      // IE 9, 10
      event.preventDefault();
    }
  };

  return useCallback((element) => {
    if (element && !controls.current.includes(element)) {
      controls.current.push(element);
      element.addEventListener('keydown', handler);
    }
  }, []);
};

...
const focusNextRef = useFocusNext();

<input ref={focusNextRef} />
<input ref={focusNextRef} />
<button ref={focusNextRef}>Submit</button>

代码笔

您可以通过 for-in 循环使用 componentDidMount 和自动绑定引用。

http://codepen.io/jzmmm/pen/PzZgRX?editors=0010

  constructor() {
    super();
    this._handleKeyPress = this._handleKeyPress.bind(this);
  }

  // Loop through the ref's object, and bind each of them to onkeypress
  componentDidMount() {
    for (let x in this.refs) {
      this.refs[x].onkeypress = (e) => 
        this._handleKeyPress(e, this.refs[x]);
    }
  }

  // This checks ENTER key (13), then checks if next node is an INPUT
  // Then focuses next input box
  _handleKeyPress(e, field) {
    if (e.keyCode === 13) {
      e.preventDefault(); // Prevent form submission if button present
      let next = this.refs[field.name].nextSibling;

      if (next && next.tagName === "INPUT") {
        this.refs[field.name].nextSibling.focus();
      }
    }
  }

  render() {
    return (
        <form>
          <input type="text" name="name" ref='name' />
          <input type="text" name="email" ref='email' />
          <input type="text" name="zip_code" ref='zip_code' />
        </form>
    );
  }

这就是我设法使它更简单的方法:

  @autobind
  handleKeyPress(value, event){
    if(event.key === 'Enter'){
      this.refs[event].focus();
    }
  }

    <input
      onKeyPress={(event) => this.handleKeyPress('email', event)}
      ref = 'name'
    />

    <input
      onKeyPress={(event) => this.handleKeyPress('zip_code', event)}
      ref = 'email'
    />

    <input
      ref = 'zip_code'
    />

没有<form>和 TypeScript 版本。跳过禁用的输入。

const onKeyPress: React.KeyboardEventHandler<HTMLInputElement> = useCallback(
  (e) => {
    if (e.key === "Enter") {
      const inputs = Array.from(
        // Get table or tbody whatever that contains all inputs. The number of parentElements depends on the structure of your html
        e.currentTarget?.parentElement?.parentElement?.parentElement?.querySelectorAll(
          "input"
        ) ?? []
      ).filter((e) => !e.disabled)
      const index = inputs.indexOf(e.currentTarget)
      inputs[index + 1]?.focus()
      e.preventDefault()
    }
  },
  []
)

return <input type="number" onKeyPress={onKeyPress} />