我想了解从另一个数组的所有元素中过滤数组的最佳方法。我尝试使用过滤器功能，但我不知道如何给它我想要删除的值。
就像是：
var array = [1,2,3,4];
var anotherOne = [2,4];
var filteredArray = array.filter(myCallback);
// filteredArray should now be [1,3]
function myCallBack(){
return element ! filteredArray;
//which clearly can't work since we don't have the reference <,<
}
如果过滤器功能没有用，您将如何实现？
编辑：我检查了可能重复的问题，它对那些容易理解 javascript 的人很有用。检查为好的答案使事情变得容易。
我会这样做；
var arr1 = [1,2,3,4],
arr2 = [2,4],
res = arr1.filter(item => !arr2.includes(item));
console.log(res);您可以使用函数的this参数filter()来避免将过滤器数组存储在全局变量中。
var filtered = [1, 2, 3, 4].filter(
function(e) {
return this.indexOf(e) < 0;
},
[2, 4]
);
console.log(filtered);var array = [1,2,3,4];
var anotherOne = [2,4];
var filteredArray = array.filter(myCallBack);
function myCallBack(el){
return anotherOne.indexOf(el) < 0;
}
在回调中，您检查每个值array是否在anotherOne
https://jsfiddle.net/0tsyc1sx/
如果您正在使用lodash.js，请使用_.difference
filteredArray = _.difference(array, anotherOne);
如果您有一组对象：
var array = [{id :1, name :"test1"},{id :2, name :"test2"},{id :3, name :"test3"},{id :4, name :"test4"}];
var anotherOne = [{id :2, name :"test2"}, {id :4, name :"test4"}];
var filteredArray = array.filter(function(array_el){
return anotherOne.filter(function(anotherOne_el){
return anotherOne_el.id == array_el.id;
}).length == 0
});
/* Here's an example that uses (some) ES6 Javascript semantics to filter an object array by another object array. */
// x = full dataset
// y = filter dataset
let x = [
{"val": 1, "text": "a"},
{"val": 2, "text": "b"},
{"val": 3, "text": "c"},
{"val": 4, "text": "d"},
{"val": 5, "text": "e"}
],
y = [
{"val": 1, "text": "a"},
{"val": 4, "text": "d"}
];
// Use map to get a simple array of "val" values. Ex: [1,4]
let yFilter = y.map(itemY => { return itemY.val; });
// Use filter and "not" includes to filter the full dataset by the filter dataset's val.
let filteredX = x.filter(itemX => !yFilter.includes(itemX.val));
// Print the result.
console.log(filteredX);下面的代码是根据另一个数组过滤一个数组的最简单方法。两个数组都可以在其中包含对象而不是值。
let array1 = [1, 3, 47, 1, 6, 7];
let array2 = [3, 6];
let filteredArray1 = array1.filter(el => array2.includes(el));
console.log(filteredArray1); 输出： [3, 6]