我创建了一个简单的 React 组件来生成菜单，我想用 Redux（而不是状态）替换它的可见性切换。

我的组件如下所示：

class SiteMenu extends React.Component {
  constructor(props) {
    super(props);
  }

  toggle(force = false) {
    let active = !active;

    store.dispatch({
      type: 'TOGGLE',
      active
    });
  }

  render() {
    const wrapperClass = this.props.active ? `${this.props.className}__wrapper ${this.props.className}__wrapper--active` : `${this.props.className}__wrapper`;
    return (
      <nav className={this.props.className} ref="nav">
        <button className={`${this.props.className}__trigger`} onClick={this.toggle.bind(this)}>
          {this.props.active}
        </button>
        <ul className={wrapperClass}>
        </ul>
      </nav>
    );
  }
}

我补充说mapStateToProps：

const mapStateToProps = (store) => {
  return {
    active: store.menuState.active
  }
};

和 connect

connect(mapStateToProps)(SiteMenu);

我的店铺：

import { createStore } from 'redux';
import reducers from './reducers/index.js';

const store = createStore(reducers, window.devToolsExtension && window.devToolsExtension());
export default store;

和减速器：

import { combineReducers } from 'redux';
import menuReducer from './menu-reducer';

const reducers = combineReducers({
  menuState: menuReducer
});

export default reducers;

const initialMenuState = {
  active: false
};

const menuReducer = (state = initialMenuState, action) => {
  switch(action.type) {
    case 'TOGGLE':
      console.log(action);
      return Object.assign({}, state, { active: action.active });
  }

  return state;
};

export default menuReducer;

当我检查我的 Redux DevTools 时，状态正在改变。我该怎么办？

存储库中的代码：https : //github.com/tomekbuszewski/react-redux