日期之间的差异，将结果四舍五入到最接近的分钟

IT技术 javascript reactjs datetime momentjs
2021-05-16 05:37:59

日期之间的差异要四舍五入到最接近的分钟。圆形date1、date2向下或向上。返回的结果已经四舍五入到整分钟。我可以修改date1，date2。不修改已经返回的结果

date2- date1

代码在这里：https : //stackblitz.com/edit/react-azau4g

例子：

第一步

this.state = {
  date1: "2019-06-29 21:25:38+00",
  date2: "2019-06-29T21:25:40.000+00:00"
}

round = (item) => {
  var m = moment(item);

  var roundUp = (m.second() || m.millisecond() ? m.add(1, 'minute').startOf('minute') : m.startOf('minute')).toISOString();
  return roundUp;
}

differentTime = {
    date1: this.state.date1.toISOString(),  
    date2: this.round(this.state.date2)   //return "2019-06-29T21:26:00.000+00:00"
}

第二步

预期效果：

data2- data1= 1 分钟

示例 2

 this.state = {
      date1: "2019-06-29 21:25:01+00",
      date2: "2019-06-29T21:27:20.000+00:00"
    }



 differentTime2 = {
        date1: this.state.date1.toISOString(), 
        date2: this.round(this.state.date2)   //return "2019-06-29T21:28:00.000+00:00"
    }

预期效果：

date2- date1= 3 分钟

3个回答

看起来您想要一个从另一个日期中减去一个日期并将差异四舍五入到最接近的分钟的函数。

这不能通过像round您问题中的函数这样的单个参数来完成；您需要一个将两个日期都作为参数的函数。

我对 moment 不太熟悉，但这里有一个适用于内置日期的函数。

编辑：根据 OP 的评论，我更新了函数以进行修改d2而不是返回差异。

    MS_IN_MINUTES = 60000;

    roundAway = (d1, d2) => {
      let diff = d2 - d1 // Difference in milliseconds (+ or -)
      let positive = diff > 0 // Whether we should add later
      diff = Math.abs(diff) // Difference in milliseconds (+)
      diff = diff / MS_IN_MINUTES // Difference in minutes (not rounded)
      diff = Math.ceil(diff) // Difference in minutes (rounded up)
      let roundedAway = d1.getTime()
      if (positive) {
          roundedAway += diff * MS_IN_MINUTES
      }
      else {
          roundedAway -= diff * MS_IN_MINUTES
      }
      d2.setTime(roundedAway)
    }
    
    let date1 = new Date("2019-06-29 21:25:38+00");
    console.log('date1:', date1)

    let date2 = new Date("2019-06-29T21:25:40.000+00:00");
    console.log('date2:', date2)

    let date3 = new Date("2019-06-29T21:24:36.000+00:00");
    console.log('date3:', date3)

    console.log('Unchanged date1:', date1);

    roundAway(date1, date2);
    console.log('Rounded date2:', date2);

    roundAway(date1, date3);
    console.log('Rounded date3:', date3);

希望有帮助！

这可能会帮助您将日期四舍五入到最接近的分钟：

const date = moment("2019-06-29T21:59:59.000+00:00");
const seconds = date.seconds();
date.add(seconds > 0 && 60 - seconds, 's');

我们可以使用该diff方法来获取毫秒数，将其转换为分钟，然后对结果进行 ceil

import moment from 'moment';

let date1 = moment("2019-06-29 21:25:38+00");
console.log(date1)

let date2 = moment("2019-06-29T21:25:40.000+00:00");
console.log(date2)

// get the difference between the moments
const diff = date2.diff(date1);
console.log(diff);

// convert to minutes and ceil
const diffInMinutes = Math.ceil(diff/60000);
console.log(diffInMinutes);
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