react-native错误:日期值不能从字符串转换为双精度

IT技术 javascript reactjs react-native
2021-05-18 12:31:53

所以,我有这个reminder componenttextInput 从 react-native 导入,DatePicker 从原生库导入,还有一个按钮可以在单击事件时保存表单。

现在当我点击日期选择器时,它给出了一个错误说:value for date cannot be cast from string to double我还附上了错误的屏幕截图。

错误截图

不知道我哪里出错了。

这是组件的代码。

class Reminder extends Component {

    constructor(props) {
        super(props);
        let formatDate = new Date();
        this.state = {
            chosenDate: formatDate.toISOString().split('T')[0],
            text: '',
        };
        this.handleChangeInput = this.handleChangeInput.bind(this);
        this.saveData = this.saveData.bind(this);
    }


    render() { 
        const {chosenDate} = this.state;
        return ( 
            <View>
                <Form style={styles.formContainer}>
                    <View style={styles.formView}>

                        < TextInput
                            placeholder = "Set your reminder"
                            onChangeText={this.handleChangeInput}
                            value={this.state.text}
                        />

                        <DatePicker
                            defaultDate={chosenDate}
                            mode = "date"
                            animationType={"fade"}
                            androidMode={"default"}
                            placeHolderText="Select date"
                            textStyle={{ color: "green" }}
                            placeHolderTextStyle={{ color: "#d3d3d3" }}
                            onDateChange={(chosenDate) => this.setState({chosenDate})}
                        />
                        <Text style={styles.datePicker}>
                            {chosenDate}
                        </Text>
                    </View>
                    <View style={styles.footer}>
                        <Button block success style={styles.saveBtn} 
                            onPress={ () => 
                                    {
                                    this.saveData()
                                    //console.log('save data', fomattedState);
                                    Alert.alert('Yay!!', 'Succefully saved.')
                                    }
                                } 
                           >
                            <Icon type='MaterialIcons' name='done' />                        
                        </Button>
                    </View>
                </Form>
            </View> 
        );
    }

    handleChangeInput = (input) => {
        this.setState({
            text: input
        });
    }

    //save the input
    saveData() {
        let {chosenDate, ...restOfState} =  this.state;
        let textArray = Object.entries(restOfState).map(([key, value])=> ({[key]: value}));
        let fomattedState = {[chosenDate]:textArray};
        console.log('formatted state', fomattedState);
        AsyncStorage.setItem("key", JSON.stringify(this.fomattedState));
    }
}
3个回答

我在这个@react-native-community/datetimepicker包中遇到了同样的问题所以我用 Moment 库和 JavaScriptDate.parse()方法修复了这个问题

const [targetDate, setTargetDate] = useState(
    new Date(
      Date.parse(
        moment(selectedGoal.targetDate, 'DD/MM/YYYY').format(
          'ddd MMM DD YYYY HH:mm:ss ZZ',
        ),
      ),
    ),
  );

该错误很可能是由于您提供的默认日期字段造成的。您正在发送一个字符串。尝试像在 Native Base 文档http://docs.nativebase.io/Components.html#date-picker-def-headref 中指定的那样设置默认日期

<DatePicker
            defaultDate={new Date(2018, 4, 4)}
            locale={"en"}
            modalTransparent={false}
            animationType={"fade"}
            androidMode={"default"}
            placeHolderText="Select date"
            textStyle={{ color: "green" }}
            placeHolderTextStyle={{ color: "#d3d3d3" }}
            onDateChange={this.setDate}
            />

如果可行,您应该解析存储在状态中 selectedDate 中的日期并发送参数,例如我提供的示例....

let dateNumbers = this.state.chosenDate.split('-');  

然后你有年、日和月

(3) ["2018", "12", "10"]

您可以将其解析为 int 每个部分,然后您就可以设置默认日期了:

  <DatePicker
                defaultDate={new Date(parseInt(dateNumbers[0]), parseInt(dateNumbers[1]),parseInt(dateNumbers[2]))}
                locale={"en"}
                modalTransparent={false}
                animationType={"fade"}
                androidMode={"default"}
                placeHolderText="Select date"
                textStyle={{ color: "green" }}
                placeHolderTextStyle={{ color: "#d3d3d3" }}
                onDateChange={this.setDate}
                />

使用@react-native-community/datetimepickerAndroid也有同样的问题(iOS 工作正常)。就我而言,我是这样解决的:

1) 状态变量:

const [isPickerOpen, setIsPickerOpen] = useState(false);
const user = useSelector(state => state.user); // Using Redux to store User's birthday
const parsedBirthday = new Date(moment(user.birthday).format('YYYY-MM-DD'));
const [birthday, setBirthday] = useState(parsedBirthday);

2) 显示 TextInput 和 Picker:

<TouchableOpacity onPress={() => showDatepicker()}>
    <TextInput
        style={styles.inputText}
        editable={false}
        pointerEvents='none'
        onTouchStart={() => { showDatePicker() }}
        value={moment(birthday).format('DD-MM-YYYY')}
    />
</TouchableOpacity>
{(isPickerOpen) ?
    <View>
        <DatePicker
            minimumDate={new Date(1901, 0, 1)}
            maximumDate={new Date()}
            value={birthday}
            mode='date'
            display='default'
            onChange={datePickerHandler} 
        />
    </View>
 : null
}

3) 处理程序:

const showDatePicker = () => {
    setIsPickerOpen(true);
}

const datePickerHandler = (event, selectedDate) => {
    const currentDate = selectedDate || birthday;
    if (Platform.OS === 'android') setIsPickerOpen(false);
    setBirthday(currentDate);
}