我在路由中有一个表单，如果有任何验证错误，它不应该允许用户导航到另一条路由。如果没有验证错误，则允许导航到另一条路线。

下面是我当前的代码，该onBlock函数不起作用对其异步性质，因为提交然后验证表单的函数是异步的。

表单组件.js

import React, { useState, useEffect, useRef } from "react";
import { FieldArray } from "formik";
import { useHistory } from "react-router-dom";
import * as Yup from "yup";
import Form from "./Form";
import TextInput from "./TextInput";

const FormComponent = () => {
  const history = useHistory();
  const [initialValues, setInitialValues] = useState();
  const [isSubmitted, setIsSubmitted] = useState(false);
  const block = useRef();

  const formRef = useRef(null);

  const onFormSubmit = async (values) => {
    setIsSubmitted(true);
  };

  const validationSchema = () => {
    const schema = {
      test: Yup.string().required("Input is Required")
    };
    return Yup.object(schema);
  };

  const onBlock = () => {
    const { submitForm, validateForm } = formRef?.current || {};
    // submit form first
    submitForm()
      .then(() => {
        // then validate form
        validateForm()
          .then(() => {
            // if form is valid - should navigate to route
            // if form is not valid - should remain on current route
            return formRef?.current.isValid;
          })
          .catch(() => false);
      })
      .catch(() => false);
  };

  const redirectToPage = () => {
    history.push("/other-page");
  };

  useEffect(() => {
    block.current = history.block(onBlock);

    return () => {
      block.current && block.current();
    };
  });

  useEffect(() => {
    if (isSubmitted) redirectToPage();
  }, [isSubmitted]);

  useEffect(() => {
    setInitialValues({
      test: ""
    });
  }, []);

  return initialValues ? (
    <Form
      initialValues={initialValues}
      onSubmit={onFormSubmit}
      formRef={formRef}
      validationSchema={validationSchema}
    >
      <FieldArray
        name="formDetails"
        render={(arrayHelpers) =>
          arrayHelpers && arrayHelpers.form && arrayHelpers.form.values
            ? (() => {
                const { form } = arrayHelpers;
                formRef.current = form;
                return (
                  <>
                    <TextInput name="test" />
                    <button type="submit">Submit</button>
                  </>
                );
              })()
            : null
        }
      />
    </Form>
  ) : null;
};

export default FormComponent;

如果用户尝试在输入中没有任何值的情况下提交表单，我希望这onBlock将返回false到块导航。但这似乎不起作用。然而，只需false在onBlock函数中返回即可。所以看起来这个history.block函数不接受任何回调。我也曾尝试将其转换为一个async功能，await在submitForm和validateForm功能，但仍然没有喜悦。有没有解决的办法？任何帮助将不胜感激。

这是带有示例的CodeSandbox。