我在数组中有 2 个对象
dataV[1] = {
"resolution": "4"
};
datas[1] = {
{qty_approved: "1", resolution: "5", status: "", order: "1332"}
}
如果两个索引相同，那么我想用第一个的值更新。我想将分辨率值从 5 更新为 4。基于 dataV 中新数组值的即将到来的值
预期输出如下：
datas[1] = {
{qty_auth: "1", resolution: "4", status: "", order: "1332"}
}
无论你在哪里更新你的value，dataV你都可以做这样的事情，更新datas：
datas = datas.map((data, i) => {
return { ...data, resolution: dataV[i].resolution };
});
如果你使用react，你可以做同样的事情在useEffect与dataV作为一个依赖。所以，无论何时dataV发生变化，datas都会自动发生变化。
let array1 = [
{
resolution: '4',
},
];
let array2 = [
{ qty_approved: '1', resolution: '5', status: '', order: '1332' },
];
let array3 = array1.map((element, index) => {
if (typeof array2[index] != 'undefined') {
return { ...array2[index], ...element};
}
return element;
});
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/map
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Spread_syntax
由于您可以通过数组索引获取相应的元素，因此您可以像以下代码段一样轻松获取相应的分辨率：
datas.forEach( (_, i) => {
datas[i].resolution = dataV[i].resolution
})
Array#reduce，dataV在更新Map索引key和分辨率的同时迭代valueArray#forEach，迭代datas，如果上面的map有这样一个索引的key，更新分辨率const
dataV = [ { "resolution": "4" }, { "resolution": "7" }, { "resolution": "1" } ],
datas = [
{ qty_approved: "1", resolution: "5", status: "", order: "1332" },
{ qty_approved: "1", resolution: "3", status: "", order: "1331" },
{ qty_approved: "1", resolution: "9", status: "", order: "1333" },
];
const indexResolutionMap = dataV.reduce((map, { resolution }, i) =>
map.set(i, resolution)
, new Map);
datas.forEach((e, i) => {
const resolution = indexResolutionMap.get(i);
if(resolution) e.resolution = resolution;
});
console.log(datas);