使用 Javascript 格式化当前时间

IT技术 javascript date time format
2021-01-31 12:18:25

我想使用 javascript 以特定格式获取当前时间。

使用下面的函数并调用它会给我 2013 年 2 月 1 日星期五 13:56:40 GMT+1300(新西兰夏令时), 但我想将其格式化为 2013 年 2 月 1 日星期五下午 2:00

var d = new Date();
var x = document.getElementById("time");
x.innerHTML = d;

当然,上面的代码没有任何格式化逻辑,但我还没有遇到任何“工作”格式化程序。

6个回答

你可能想尝试

var d = new Date();
d.toLocaleString();       // -> "2/1/2013 7:37:08 AM"
d.toLocaleDateString();   // -> "2/1/2013"
d.toLocaleTimeString();  // -> "7:38:05 AM"

文档

值得注意的是,这些方法可以采用语言环境和选项以提供更大的灵活性。例如美国 24 小时制date.toLocaleTimeString('en-US', { hour12: false }); developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/...
2021-03-18 12:18:25
为什么你的方法对我不起作用?d.toLocaleTimeString()并且d.toLocaleTimeString()不工作。
2021-03-31 12:18:25
是的。我没有找到任何方法toLocaleTimeString()toLocaleTimeString()
2021-04-01 12:18:25
afzalex 试试这个: new Date().toLocaleString();
2021-04-06 12:18:25
@afzalex 你的意思是你没有得到任何回报?
2021-04-10 12:18:25

JavaScript 日期有多种方法允许您提取其部分:

getFullYear()- 返回 4 位年份
getMonth()- 返回一个从零开始的整数 (0-11),表示一年中的月份。
getDate()- 返回一个月中的第几天 (1-31)。
getDay()- 返回星期几 (0-6)。0 是星期日,6 是星期六。
getHours()- 返回一天中的小时 (0-23)。
getMinutes()- 返回分钟 (0-59)。
getSeconds()- 返回第二个 (0-59)。
getMilliseconds()- 返回毫秒 (0-999)。
getTimezoneOffset()- 返回机器本地时间和 UTC 之间的分钟数。

没有内置方法允许您获取本地化的字符串,例如“Friday”、“February”或“PM”。你必须自己编码。要获得您想要的字符串,您至少需要存储日期和月份的字符串表示形式:

var months = ["Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"];
var days = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"];

然后,使用上述方法将其组合在一起:

var months = ["Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"];
var days = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"];
var d = new Date();
var day = days[d.getDay()];
var hr = d.getHours();
var min = d.getMinutes();
if (min < 10) {
    min = "0" + min;
}
var ampm = "am";
if( hr > 12 ) {
    hr -= 12;
    ampm = "pm";
}
var date = d.getDate();
var month = months[d.getMonth()];
var year = d.getFullYear();
var x = document.getElementById("time");
x.innerHTML = day + " " + hr + ":" + min + ampm + " " + date + " " + month + " " + year;
<span id="time"></span>

我有一个我喜欢包含在我的标准库中的日期格式函数。它采用定义所需输出的格式字符串参数。格式字符串松散地基于.Net 自定义日期和时间格式字符串对于您指定的格式,以下格式字符串将起作用: "dddd h:mmtt d MMM yyyy".

var d = new Date();
var x = document.getElementById("time");
x.innerHTML = formatDate(d, "dddd h:mmtt d MMM yyyy");

演示: jsfiddle.net/BNkkB/1

这是我的完整日期格式化功能:

function formatDate(date, format, utc) {
    var MMMM = ["\x00", "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
    var MMM = ["\x01", "Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"];
    var dddd = ["\x02", "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"];
    var ddd = ["\x03", "Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat"];

    function ii(i, len) {
        var s = i + "";
        len = len || 2;
        while (s.length < len) s = "0" + s;
        return s;
    }

    var y = utc ? date.getUTCFullYear() : date.getFullYear();
    format = format.replace(/(^|[^\\])yyyy+/g, "$1" + y);
    format = format.replace(/(^|[^\\])yy/g, "$1" + y.toString().substr(2, 2));
    format = format.replace(/(^|[^\\])y/g, "$1" + y);

    var M = (utc ? date.getUTCMonth() : date.getMonth()) + 1;
    format = format.replace(/(^|[^\\])MMMM+/g, "$1" + MMMM[0]);
    format = format.replace(/(^|[^\\])MMM/g, "$1" + MMM[0]);
    format = format.replace(/(^|[^\\])MM/g, "$1" + ii(M));
    format = format.replace(/(^|[^\\])M/g, "$1" + M);

    var d = utc ? date.getUTCDate() : date.getDate();
    format = format.replace(/(^|[^\\])dddd+/g, "$1" + dddd[0]);
    format = format.replace(/(^|[^\\])ddd/g, "$1" + ddd[0]);
    format = format.replace(/(^|[^\\])dd/g, "$1" + ii(d));
    format = format.replace(/(^|[^\\])d/g, "$1" + d);

    var H = utc ? date.getUTCHours() : date.getHours();
    format = format.replace(/(^|[^\\])HH+/g, "$1" + ii(H));
    format = format.replace(/(^|[^\\])H/g, "$1" + H);

    var h = H > 12 ? H - 12 : H == 0 ? 12 : H;
    format = format.replace(/(^|[^\\])hh+/g, "$1" + ii(h));
    format = format.replace(/(^|[^\\])h/g, "$1" + h);

    var m = utc ? date.getUTCMinutes() : date.getMinutes();
    format = format.replace(/(^|[^\\])mm+/g, "$1" + ii(m));
    format = format.replace(/(^|[^\\])m/g, "$1" + m);

    var s = utc ? date.getUTCSeconds() : date.getSeconds();
    format = format.replace(/(^|[^\\])ss+/g, "$1" + ii(s));
    format = format.replace(/(^|[^\\])s/g, "$1" + s);

    var f = utc ? date.getUTCMilliseconds() : date.getMilliseconds();
    format = format.replace(/(^|[^\\])fff+/g, "$1" + ii(f, 3));
    f = Math.round(f / 10);
    format = format.replace(/(^|[^\\])ff/g, "$1" + ii(f));
    f = Math.round(f / 10);
    format = format.replace(/(^|[^\\])f/g, "$1" + f);

    var T = H < 12 ? "AM" : "PM";
    format = format.replace(/(^|[^\\])TT+/g, "$1" + T);
    format = format.replace(/(^|[^\\])T/g, "$1" + T.charAt(0));

    var t = T.toLowerCase();
    format = format.replace(/(^|[^\\])tt+/g, "$1" + t);
    format = format.replace(/(^|[^\\])t/g, "$1" + t.charAt(0));

    var tz = -date.getTimezoneOffset();
    var K = utc || !tz ? "Z" : tz > 0 ? "+" : "-";
    if (!utc) {
        tz = Math.abs(tz);
        var tzHrs = Math.floor(tz / 60);
        var tzMin = tz % 60;
        K += ii(tzHrs) + ":" + ii(tzMin);
    }
    format = format.replace(/(^|[^\\])K/g, "$1" + K);

    var day = (utc ? date.getUTCDay() : date.getDay()) + 1;
    format = format.replace(new RegExp(dddd[0], "g"), dddd[day]);
    format = format.replace(new RegExp(ddd[0], "g"), ddd[day]);

    format = format.replace(new RegExp(MMMM[0], "g"), MMMM[M]);
    format = format.replace(new RegExp(MMM[0], "g"), MMM[M]);

    format = format.replace(/\\(.)/g, "$1");

    return format;
};
如何MMMM[0]在索引 0 处返回正确的月份名称而不是不可打印的字符?不应该MMMM[M]吗?我只是傻吗?(没关系。它将它设置为不可打印的字符,稍后将其替换以避免冲突)
2021-03-14 12:18:25
我如何格式化 date = "2016/03/01 11:00" to date ="Sat Mar 01 2016 11:00:00 GMT+0530 (IST)"
2021-03-16 12:18:25
非常感谢。虽然我的最终代码需要一些调整,但您的见解有所帮助。
2021-04-10 12:18:25

2017 更新:使用toLocaleDateStringtoLocaleTimeString来格式化日期和时间。传递给这些方法的第一个参数是区域设置值,例如en-us第二个参数(如果存在)指定格式选项,例如工作日的长格式。

let date = new Date();  
let options = {  
    weekday: "long", year: "numeric", month: "short",  
    day: "numeric", hour: "2-digit", minute: "2-digit"  
};  

console.log(date.toLocaleTimeString("en-us", options)); 

输出:2017 年 10 月 25 日,星期三,晚上 8:19

请参阅以下链接了解更多详情。

日期和时间字符串 (JavaScript)

撕裂。@thdoan 的 strftime 端口看起来更灵活。例如,toLocalTimeString提供 4 种日期样式,full long medium short并且可能在某处定义了这些术语的含义。同时, strftime 可以(可能)匹配其中任何一个以及更多。另一方面,toLocalTimeString支持时区。我希望包括使用夏令时的时区......
2021-04-04 12:18:25
此时 - 在首次回答这个问题四年后 - 这是现在最方便和灵活的解决方案,并回答这个问题。作为当前(AD 2018)实践的一个例子,它应该得到更高的提升:-)
2021-04-07 12:18:25
完美的答案,解决了整个问题。我认为缺少指向 toLocaleString() 的链接,其中直接描述了参数和选项
2021-04-07 12:18:25

您可以使用我的strftime端口

/* Port of strftime(). Compatibility notes:
 *
 * %c - formatted string is slightly different
 * %D - not implemented (use "%m/%d/%y" or "%d/%m/%y")
 * %e - space is not added
 * %E - not implemented
 * %h - not implemented (use "%b")
 * %k - space is not added
 * %n - not implemented (use "\n")
 * %O - not implemented
 * %r - not implemented (use "%I:%M:%S %p")
 * %R - not implemented (use "%H:%M")
 * %t - not implemented (use "\t")
 * %T - not implemented (use "%H:%M:%S")
 * %U - not implemented
 * %W - not implemented
 * %+ - not implemented
 * %% - not implemented (use "%")
 *
 * strftime() reference:
 * http://man7.org/linux/man-pages/man3/strftime.3.html
 *
 * Day of year (%j) code based on Joe Orost's answer:
 * http://stackoverflow.com/questions/8619879/javascript-calculate-the-day-of-the-year-1-366
 *
 * Week number (%V) code based on Taco van den Broek's prototype:
 * http://techblog.procurios.nl/k/news/view/33796/14863/calculate-iso-8601-week-and-year-in-javascript.html
 */
function strftime(sFormat, date) {
  if (!(date instanceof Date)) date = new Date();
  var nDay = date.getDay(),
    nDate = date.getDate(),
    nMonth = date.getMonth(),
    nYear = date.getFullYear(),
    nHour = date.getHours(),
    aDays = ['Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday'],
    aMonths = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December'],
    aDayCount = [0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334],
    isLeapYear = function() {
      if ((nYear&3)!==0) return false;
      return nYear%100!==0 || nYear%400===0;
    },
    getThursday = function() {
      var target = new Date(date);
      target.setDate(nDate - ((nDay+6)%7) + 3);
      return target;
    },
    zeroPad = function(nNum, nPad) {
      return ('' + (Math.pow(10, nPad) + nNum)).slice(1);
    };
  return sFormat.replace(/%[a-z]/gi, function(sMatch) {
    return {
      '%a': aDays[nDay].slice(0,3),
      '%A': aDays[nDay],
      '%b': aMonths[nMonth].slice(0,3),
      '%B': aMonths[nMonth],
      '%c': date.toUTCString(),
      '%C': Math.floor(nYear/100),
      '%d': zeroPad(nDate, 2),
      '%e': nDate,
      '%F': date.toISOString().slice(0,10),
      '%G': getThursday().getFullYear(),
      '%g': ('' + getThursday().getFullYear()).slice(2),
      '%H': zeroPad(nHour, 2),
      '%I': zeroPad((nHour+11)%12 + 1, 2),
      '%j': zeroPad(aDayCount[nMonth] + nDate + ((nMonth>1 && isLeapYear()) ? 1 : 0), 3),
      '%k': '' + nHour,
      '%l': (nHour+11)%12 + 1,
      '%m': zeroPad(nMonth + 1, 2),
      '%M': zeroPad(date.getMinutes(), 2),
      '%p': (nHour<12) ? 'AM' : 'PM',
      '%P': (nHour<12) ? 'am' : 'pm',
      '%s': Math.round(date.getTime()/1000),
      '%S': zeroPad(date.getSeconds(), 2),
      '%u': nDay || 7,
      '%V': (function() {
              var target = getThursday(),
                n1stThu = target.valueOf();
              target.setMonth(0, 1);
              var nJan1 = target.getDay();
              if (nJan1!==4) target.setMonth(0, 1 + ((4-nJan1)+7)%7);
              return zeroPad(1 + Math.ceil((n1stThu-target)/604800000), 2);
            })(),
      '%w': '' + nDay,
      '%x': date.toLocaleDateString(),
      '%X': date.toLocaleTimeString(),
      '%y': ('' + nYear).slice(2),
      '%Y': nYear,
      '%z': date.toTimeString().replace(/.+GMT([+-]\d+).+/, '$1'),
      '%Z': date.toTimeString().replace(/.+\((.+?)\)$/, '$1')
    }[sMatch] || sMatch;
  });
}

示例用法:

// Returns "Thursday 4:45pm 15 Sep 2016"
strftime('%A %l:%M%P %e %b %Y');

// You can optionally pass it a Date object
// Returns "Friday 2:00pm 1 Feb 2013"
strftime('%A %l:%M%P %e %b %Y', new Date('Feb 1, 2013 2:00 PM'));

最新代码可在此处获得:https : //github.com/thdoan/strftime

这太棒了。太感谢了。
2021-03-19 12:18:25

查看 Date 类的内部结构,您将看到可以提取所有位(日期、月份、年份、小时等)。

http://www.w3schools.com/jsref/jsref_obj_date.asp

对于类似Fri 23:00 1 Feb 2013的代码是这样的:

date = new Date();

weekdayNames = ['Sun', 'Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat'];
monthNames = ["Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"];
var dateString = weekdayNames[date.getDay()] + " " 
    + date.getHours() + ":" + ("00" + date.getMinutes()).slice(-2) + " " 
    + date.getDate() + " " + monthNames[date.getMonth()] + " " + date.getFullYear();

console.log(dateString);

**** 修改 2019-05-29 以保持 3 位投票者满意

Date#getDay 返回一个整数,而不是工作日的名称。此外,恕我直言,MDN 在快速理解 Date 对象方面做得更糟,所以我不明白为什么需要贬低。
2021-03-15 12:18:25
问题date.getMinutes()在于,当分钟数小于 10 时,它返回一位数,导致时间类似于“10:4 am”而不是更常见的“10:04 am”。
2021-03-16 12:18:25
w3schools 不是很好。w3fools更好的参考来源包括MDNMSDN
2021-03-17 12:18:25
@Ninjaxor 添加了非日期相关代码以将数字转换为字符串。如果你想要英文名字,这应该有效。
2021-03-27 12:18:25
@JochemSchulenklopper 添加了非日期代码以在分钟内显示前导零
2021-03-30 12:18:25