我想验证该值是否为有效的 IP 地址..！
我曾经验证过
ValidIpAddressRegex = "^(([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])\.){3}([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])$";
它工作正常，但是当我给出类似的值时12345678，它也返回true .. 如何解决这个问题？
IP 地址验证的正则表达式
IT技术
javascript
regex
2021-02-09 02:36:37
6个回答
有一个更简单的方法。您只需要拆分字符串.并检查每个数字是否在 0 到 255 之间。
此外，您可以检查 hexa 并拆分:IPv6。
只是因为我觉得这很有趣：
^(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5]))\.(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5]))\.(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5]))\.(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5]))$
这是一个应该处理 IP (v4) 的正则表达式。
为 IPv4 寻找一个，我最终只是自己创建了它。（这仅处理常见的虚线变体，即 0.0.0.0 - 255.255.255.255）
^ # START OF STRING
(?=\d+\.\d+\.\d+\.\d+$) # Lookahead, require this format: number.number.number.number END OF STRING
(?: # Start non-capture group (number 0-255 + optional dot)
(?: # Start non-capture group (number 0-255)
25[0-5] # 250-255
| # OR
2[0-4][0-9] # 200-249
| # OR
1[0-9]{2} # 100-199
| # OR
[1-9][0-9] # 10-99
| # OR
[0-9] # 0-9
) # End non-capture group
\.? # Optional dot (enforced in correct positions by lookahead)
){4} # End non-capture group (number + optional dot), repeat 4 times
$ # END OF STRING
没有评论：
^(?=\d+\.\d+\.\d+\.\d+$)(?:(?:25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.?){4}$
一些代码来测试它：
function isValidIpv4Addr(ip) {
return /^(?=\d+\.\d+\.\d+\.\d+$)(?:(?:25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.?){4}$/.test(ip);
}
var testAddr = ['192.68.35.35','0.0.0.0','255.0.0.0','192.168.1.0','192.168.0.1','255.255.255.0','1.1.1.1','255.255.255.255','249.249.249.249','200.200.200.200','199.199.199.199','100.100.100.100','99.99.99.99','0.0.0.0','9.9.9.9','10.10.10.10','99.99.99.99','100.100.100.100','109.109.109.109','110.110.110.110','199.199.199.199','200.200.200.200','249.249.249.249','250.250.250.250','255.255.255.255','256.256.256.260','192.168.0.0/24','192.168..1','192.168.1','1','1.','1.1','1.1.','1.1.1','1.1.1.','1.1.1.1.','1.1.1.1.1','.1.1.1.1','01.01.01.01','09.09.09.09','1.0.0.1.0','010.1.1.1','123456','123123123123','.127.0.0.1'];
for (var i = 0; i < testAddr.length; i++) {
document.getElementById('ipv4tests').innerHTML += '<li>' + testAddr[i] + ' ' + (isValidIpv4Addr(testAddr[i]) ? '<font color="green">VALID!</font>' : '<font color="red">INVALID!</font>') + '</li>';
}<ul id="ipv4tests"></ul>这适用于所有可能的情况。
^(([1-9]?\d|1\d\d|2[0-5][0-5]|2[0-4]\d)\.){3}([1-9]?\d|1\d\d|2[0-5][0-5]|2[0-4]\d)$
我知道这是旧的，但试试这个：
/^(?:(?:2[0-4]\d|25[0-5]|1\d{2}|[1-9]?\d)\.){3}(?:2[0-4]\d|25[0-5]|1\d{2}|[1-9]?\d)(?:\:(?:\d|[1-9]\d{1,3}|[1-5]\d{4}|6[0-4]\d{3}|65[0-4]\d{2}|655[0-2]\d|6553[0-5]))?$/
我今天为 php 中的一个函数做了它。
它处理从 0.0.0.0 到 255.255.255.255 的 ip 和从 0 到 65535 的端口。
例子：
validates:
0.0.0.0:0
255.0.0.0
192.168.1.0:8080
does not validate:
192.168.0.0/24
192.168..1
192.168.1
我知道这是一个 frankenregex，但它仍然有效！
如果端口无关紧要，请使用这个：
/^(?:(?:2[0-4]\d|25[0-5]|1\d{2}|[1-9]?\d)\.){3}(?:2[0-4]\d|25[0-5]|1\d{2}|[1-9]?\d)$/
试试这个缩短的：
^(([1-9]?\d|1\d\d|2[0-4]\d|25[0-5])(\.(?!$)|(?=$))){4}$
这是此正则表达式的测试用例：
function verifyIp(ip)
{
return /^(([1-9]?\d|1\d\d|2[0-4]\d|25[0-5])(\.(?!$)|(?=$))){4}$/.test(ip||"");
}
["192.68.35.35","0.0.0.0","255.0.0.0","192.168.1.0","192.168.0.1","255.255.255.0","1.1.1.1","255.255.255.255","249.249.249.249","200.200.200.200","199.199.199.199","100.100.100.100","99.99.99.99","0.0.0.0","9.9.9.9","10.10.10.10","99.99.99.99","100.100.100.100","109.109.109.109","110.110.110.110","199.199.199.199","200.200.200.200","249.249.249.249","250.250.250.250","255.255.255.255","256.256.256.260","192.168.0.0/24","192.168..1","192.168.1","1","1.","1.1","1.1.","1.1.1","1.1.1.","1.1.1.1.","1.1.1.1.1",".1.1.1.1","01.01.01.01","09.09.09.09","1.0.0.1.0","010.1.1.1","123456","123123123123",".127.0.0.1"].forEach(function(item){
is_valid = verifyIp(item);
$('<div>'+item+' <span class="'+(is_valid?'correct':'wrong')+'">'+(is_valid?'VALID':'INVALID')+'</span></div>').appendTo('#result');
});.item {
font-weight: bold;
}
.wrong {
color: red;
}
.correct {
color: green;
}<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="result"></div>