(更新) V5.1 & Hooks (需要 React >= 16.8)

您可以在组件中使用useHistory,useLocation和useRouteMatch来获取match,history和location。

const Child = () => {
  const location = useLocation();
  const history = useHistory();
  const match = useRouteMatch("write-the-url-you-want-to-match-here");

  return (
    <div>{location.pathname}</div>
  )
}

export default Child

(更新) V4 & V5

您可以使用withRouterHOC 来注入match,history并location在您的组件props中。

class Child extends React.Component {
  static propTypes = {
    match: PropTypes.object.isRequired,
    location: PropTypes.object.isRequired,
    history: PropTypes.object.isRequired
  }

  render() {
    const { match, location, history } = this.props

    return (
      <div>{location.pathname}</div>
    )
  }
}

export default withRouter(Child)

(更新) V3

你可以使用withRouterHOC 来在你的组件 props 中注入router, params, location, routes。

class Child extends React.Component {

  render() {
    const { router, params, location, routes } = this.props

    return (
      <div>{location.pathname}</div>
    )
  }
}

export default withRouter(Child)

原答案

如果你不想使用 props，你可以使用React Router 文档中描述的上下文

首先，您必须设置您的childContextTypes和getChildContext

class App extends React.Component{

  getChildContext() {
    return {
      location: this.props.location
    }
  }

  render() {
    return <Child/>;
  }
}

App.childContextTypes = {
    location: React.PropTypes.object
}

然后，您将能够使用这样的上下文访问子组件中的位置对象

class Child extends React.Component{

   render() {
     return (
       <div>{this.context.location.pathname}</div>
     )
   }

}

Child.contextTypes = {
    location: React.PropTypes.object
 }

如果上述解决方案对您不起作用，您可以使用 import { withRouter } from 'react-router-dom';

使用它，您可以将您的子类导出为 -

class MyApp extends Component{
    // your code
}

export default withRouter(MyApp);

还有你的路由器课程 -

// your code
<Router>
      ...
      <Route path="/myapp" component={MyApp} />
      // or if you are sending additional fields
      <Route path="/myapp" component={() =><MyApp process={...} />} />
<Router>