我需要帮助将 javascript 中的字符串按空格 (" ") 拆分，忽略引号表达式中的空格。
我有这个字符串：
var str = 'Time:"Last 7 Days" Time:"Last 30 Days"';
我希望我的字符串被拆分为 2：
['Time:"Last 7 Days"', 'Time:"Last 30 Days"']
但我的代码拆分为 4：
['Time:', '"Last 7 Days"', 'Time:', '"Last 30 Days"']
这是我的代码：
str.match(/(".*?"|[^"\s]+)(?=\s*|\s*$)/g);
谢谢！
s = 'Time:"Last 7 Days" Time:"Last 30 Days"'
s.match(/(?:[^\s"]+|"[^"]*")+/g)
// -> ['Time:"Last 7 Days"', 'Time:"Last 30 Days"']
解释：
(?: # non-capturing group
[^\s"]+ # anything that's not a space or a double-quote
| # or…
" # opening double-quote
[^"]* # …followed by zero or more chacacters that are not a double-quote
" # …closing double-quote
)+ # each match is one or more of the things described in the group
事实证明，要修复您的原始表达式，您只需要+在组上添加一个：
str.match(/(".*?"|[^"\s]+)+(?=\s*|\s*$)/g)
# ^ here.
ES6 解决方案支持：
代码：
str.match(/\\?.|^$/g).reduce((p, c) => {
if(c === '"'){
p.quote ^= 1;
}else if(!p.quote && c === ' '){
p.a.push('');
}else{
p.a[p.a.length-1] += c.replace(/\\(.)/,"$1");
}
return p;
}, {a: ['']}).a
输出：
[ 'Time:Last 7 Days', 'Time:Last 30 Days' ]
这对我有用..
var myString = 'foo bar "sdkgyu sdkjbh zkdjv" baz "qux quux" skduy "zsk"'; console.log(myString.split(/([^\s"]+|"[^"]*")+/g));
输出： 数组 ["", "foo", " ", "bar", " ", ""sdkgyu sdkjbh zkdjv"", " ", "baz", " ", ""qux quux"", " ", " skduy", " ", ""zsk"", ""]