演示

使用您提供的数据：

var data = [
    ["fruits","frozen","fresh","rotten"],
    ["apples",884,494,494],
    ["oranges",4848,494,4949],
    ["kiwi",848,33,33]
]

以下函数将数组的第一个元素视为对象属性的键。然后它将遍历剩余的元素，并使用这些键将它们转换为一个对象。最后，它将返回这些新对象的数组。

function convertToArrayOfObjects(data) {
    var keys = data.shift(),
        i = 0, k = 0,
        obj = null,
        output = [];

    for (i = 0; i < data.length; i++) {
        obj = {};

        for (k = 0; k < keys.length; k++) {
            obj[keys[k]] = data[i][k];
        }

        output.push(obj);
    }

    return output;
}

输出

[
    { fruits: 'apples', fresh: 494, frozen: 884, rotten: 494 },
    { fruits: 'oranges', fresh: 494, frozen: 4848, rotten: 4949 },
    { fruits: 'kiwi', fresh: 33, frozen: 848, rotten: 33 }
]

如果同时使用 map 和 reduce，解决方案就变得非常优雅：

var collection = [
    ["fruits","frozen","fresh","rotten"],
    ["apples",884,494,494],
    ["oranges",4848,494,4949],
    ["kiwi",848,33,33]
];

var keys = collection.shift();
collection = collection.map(function (row) {
    return keys.reduce(function (obj, key, i) {
      obj[key] = row[i];
      return obj;
    }, {});
});

输出：

[ 
  { fruits: 'apples', frozen: 884, fresh: 494, rotten: 494 },
  { fruits: 'oranges', frozen: 4848, fresh: 494, rotten: 4949 },
  { fruits: 'kiwi', frozen: 848, fresh: 33, rotten: 33 } 
]

一可避免两次迭代使用shift()+ map()+ forEach()：

var data = [
    ["fruits","frozen","fresh","rotten"],
    ["apples",884,494,494],
    ["oranges",4848,494,4949],
    ["kiwi",848,33,33]
];

var collection = data.slice(); // make a copy
var keys = collection.shift();

collection = collection.map(function (e) {
    var obj = {};

    keys.forEach(function (key, i) {
        obj[key] = e[i];
    });

    return obj;
});

演示：http : //jsfiddle.net/d7W76/2/

破坏：

const data = [
    ["fruits","frozen","fresh","rotten"],
    ["apples",884,494,494],
    ["oranges",4848,494,4949],
    ["kiwi",848,33,33]
]
const titles = data[0]
const obj = data.slice(1).map(([fruits,frozen,fresh,rotten]) => ({ fruits,frozen,fresh,rotten }) )
console.log(obj)