我试图找到一些 javascript 代码，以这种格式写入当前日期：mmddyy
我发现的所有东西都使用 4 位数年份，我需要 2 位数。
如何使用 Javascript 获得 2 位数的年份？
IT技术
javascript
date
2021-02-25 22:00:09
5个回答
这个问题的具体答案可以在下面的这一行中找到：
//pull the last two digits of the year
//logs to console
//creates a new date object (has the current date and time by default)
//gets the full year from the date object (currently 2017)
//converts the variable to a string
//gets the substring backwards by 2 characters (last two characters)
console.log(new Date().getFullYear().toString().substr(-2));格式化完整日期时间示例，单一功能 (MMddyy)：jsFiddle
JavaScript：
//A function for formatting a date to MMddyy
function formatDate(d)
{
//get the month
var month = d.getMonth();
//get the day
//convert day to string
var day = d.getDate().toString();
//get the year
var year = d.getFullYear();
//pull the last two digits of the year
year = year.toString().substr(-2);
//increment month by 1 since it is 0 indexed
//converts month to a string
month = (month + 1).toString();
//if month is 1-9 pad right with a 0 for two digits
if (month.length === 1)
{
month = "0" + month;
}
//if day is between 1-9 pad right with a 0 for two digits
if (day.length === 1)
{
day = "0" + day;
}
//return the string "MMddyy"
return month + day + year;
}
var d = new Date();
console.log(formatDate(d));格式化完整日期示例，多个函数 (MMddyy)：
// function getMonth with 1 parameter expecting date
// This function returns a string of type MM (example: 05 = May)
function getMonth(d) {
//get the month
var month = d.getMonth();
//increment month by 1 since it is 0 indexed
//converts month to a string
month = (month + 1).toString();
//if month is 1-9 pad right with a 0 for two digits
if (month.length === 1)
{
month = "0" + month;
}
return month;
}
// function getDay with 1 parameter expecting date
// This function returns a string of type dd (example: 09 = The 9th day of the month)
function getDay(d) {
//get the day
//convert day to string
var day = d.getDate().toString();
//if day is between 1-9 pad right with a 0 for two digits
if (day.length === 1)
{
day = "0" + day;
}
return day;
}
// function getYear with 1 parameter expecting date
// This function returns the year in format yy (example: 21 = 2021)
function getYear(d) {
//get the year
var year = d.getFullYear();
//pull the last two digits of the year
year = year.toString().substr(-2);
return year;
}
//A function for formatting a date to MMddyy
function formatDate(d)
{
//return the string "MMddyy"
return getMonth(d) + getDay(d) + getYear(d);
}
var d = new Date();
console.log(formatDate(d));给定一个日期对象：
date.getFullYear().toString().substr(2,2);
它将数字作为字符串返回。如果你想要它作为整数，只需将它包装在parseInt()函数中：
var twoDigitsYear = parseInt(date.getFullYear().toString().substr(2,2), 10);
在一行中显示当前年份的示例：
var twoDigitsCurrentYear = parseInt(new Date().getFullYear().toString().substr(2,2));
var d = new Date();
var n = d.getFullYear();
是的， n 会给你 4 位数字的年份，但你总是可以使用子字符串或类似的东西来分割年份，从而只给你两位数字：
var final = n.toString().substring(2);
这将为您提供年份的最后两位数字（2013 年将变为 13，等等...）
如果有更好的方法，希望有人发布它！这是我能想到的唯一方法。让我们知道它是否有效！
var currentYear = (new Date()).getFullYear();
var twoLastDigits = currentYear%100;
var formatedTwoLastDigits = "";
if (twoLastDigits <10 ) {
formatedTwoLastDigits = "0" + twoLastDigits;
} else {
formatedTwoLastDigits = "" + twoLastDigits;
}
另一个版本：
var yy = (new Date().getFullYear()+'').slice(-2);
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