到底如何在react-router 中使用嵌套路由，特别是 4.x 版？以下在以前的版本中运行良好...
<Route path='/stuff' component={Stuff}>
<Route path='/stuff/a' component={StuffA} />
</Route>
升级到 4.x 会引发以下警告...
警告：您不应在同一路由中使用 <Route> 组件和 <Route children>；<路由子项> 将被忽略
这到底是怎么回事？我已经搜索了几个小时的文档，但无法成功使嵌套路由正常工作。如何使用<Route>组件在 react-router v4 中嵌套路由？我的简单示例如何转换为 v4.x API 合规性以嵌套路由？
忘记你对 React Router < v4 的了解。您可以通过字面嵌套来嵌套路由<Routes>。检查这个例子。具体查看主题组件。您不会预先声明路由，而是在组件呈现时动态声明。
import React from 'react'
import {
BrowserRouter as Router,
Route,
Link
} from 'react-router-dom'
const BasicExample = () => (
<Router>
<div>
<ul>
<li><Link to="/">Home</Link></li>
<li><Link to="/about">About</Link></li>
<li><Link to="/topics">Topics</Link></li>
</ul>
<hr/>
<Route exact path="/" component={Home}/>
<Route path="/about" component={About}/>
<Route path="/topics" component={Topics}/>
</div>
</Router>
)
const Home = () => (
<div>
<h2>Home</h2>
</div>
)
const About = () => (
<div>
<h2>About</h2>
</div>
)
const Topics = ({ match }) => (
<div>
<h2>Topics</h2>
<ul>
<li>
<Link to={`${match.url}/rendering`}>
Rendering with React
</Link>
</li>
<li>
<Link to={`${match.url}/components`}>
Components
</Link>
</li>
<li>
<Link to={`${match.url}/props-v-state`}>
Props v. State
</Link>
</li>
</ul>
{/* NESTED ROUTES */}
<Route path={`${match.url}/:topicId`} component={Topic}/>
<Route exact path={match.url} render={() => (
<h3>Please select a topic.</h3>
)}/>
</div>
)
const Topic = ({ match }) => (
<div>
<h3>{match.params.topicId}</h3>
</div>
)
export default BasicExample
使用 react-router v4和v5，您还可以使用renderprop 来嵌套路由
<Route
path='/stuff'
render={({ match: { url } }) => (
<>
<Route path={`${url}/`} component={Stuff} exact />
<Route path={`${url}/a`} component={StuffA} />
</>
)}
/>
在我看来，与将子路由拆分为通过componentprop传入的单独定义的组件相比，这种语法在大多数情况下最终更具可读性。