我在 TypeScript 中使用 React.js。有没有办法创建继承自其他组件但有一些额外props/状态的 React 组件?
我想要实现的是这样的:
interface BaseStates {
a: number;
}
class GenericBase<S extends BaseStates> extends React.Component<void, S> {
protected getBaseInitialState(): BaseStates {
return { a: 3 };
}
}
class Base extends GenericBase<BaseStates> {
getInitialState(): BaseStates {
return super.getBaseInitialState();
}
}
interface DerivedStates extends BaseStates {
b: number;
}
class Derived extends GenericBase<DerivedStates> {
getInitialState(): DerivedStates {
var initialStates = super.getBaseInitialState() as DerivedStates; // unsafe??
initialStates.b = 4;
return initialStates
}
}
但是,如果我把这个会失败this.setState
中Derived
,我得到一个错误的typescript(类型的参数DerivedStates
是不能分配给类型S
)。我想这不是 TypeScript 特定的东西,而是将继承与泛型 (?) 混合使用的一般限制。是否有任何类型安全的解决方法?
更新
我确定的解决方案(基于 David Sherret 的回答):
interface BaseStates {
a: number;
}
class GenericBase<S extends BaseStates> extends React.Component<void, S> {
constructor() {
super();
this.state = this.getInitialState();
}
getInitialState(): S {
return { a: 3 } as S;
}
update() {
this.setState({ a: 7 } as S);
}
}
interface DerivedStates extends BaseStates {
b: number;
}
class Derived extends GenericBase<DerivedStates> {
getInitialState(): DerivedStates {
var initialStates = super.getInitialState();
initialStates.b = 4;
return initialStates;
}
update() {
this.setState({ a: 7, b: 4 });
}
}