以下是您可以如何解决这个问题：

HTML

<p id="emails"></p>

JavaScript

var text = 'sdabhikagathara@rediffmail.com, "assdsdf" <dsfassdfhsdfarkal@gmail.com>, "rodnsdfald ferdfnson" <rfernsdfson@gmal.com>, "Affdmdol Gondfgale" <gyfanamosl@gmail.com>, "truform techno" <pidfpinfg@truformdftechnoproducts.com>, "NiTsdfeSh ThIdfsKaRe" <nthfsskare@ysahoo.in>, "akasdfsh kasdfstla" <akashkatsdfsa@yahsdfsfoo.in>, "Bisdsdfamal Prakaasdsh" <bimsdaalprakash@live.com>,; "milisdfsfnd ansdfasdfnsftwar" <dfdmilifsd.ensfdfcogndfdfatia@gmail.com> datum eternus hello+11@gmail.com';    

function extractEmails (text)
{
    return text.match(/([a-zA-Z0-9._+-]+@[a-zA-Z0-9._-]+\.[a-zA-Z0-9._-]+)/gi);
}
     
$("#emails").text(extractEmails(text).join('\n'));

结果

sdabhikagathara@rediffmail.com,dsfassdfhsdfarkal@gmail.com,rfernsdfson@gmal.com,gyfanamosl@gmail.com,pidfpinfg@truformdftechnoproducts.com,nthfsskare@ysahoo.in,akashkatsdfsa@yahsdfsfoo.in,bimsdaalprakash@live.com,dfdmilifsd.ensfdfcogndfdfatia@gmail.com,hello+11@gmail.com

来源：从批量文本中提取电子邮件（使用正则表达式、JavaScript 和 jQuery）

演示 1 这里

Demo 2 这里使用 jQuery 的 each 迭代器函数

您可以使用此正则表达式：

var re = /(([^<>()[\]\\.,;:\s@\"]+(\.[^<>()[\]\\.,;:\s@\"]+)*)|(\".+\"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))/g;

您可以像这样提取电子邮件：

('sdabhikagathara@rediffmail.com, "assdsdf" <dsfassdfhsdfarkal@gmail.com>, "rodnsdfald ferdfnson" <rfernsdfson@gmail.com>, "Affdmdol Gondfgale" <gyfanamosl@gmail.com>, "truform techno" <pidfpinfg@truformdftechnoproducts.com>, "NiTsdfeSh ThIdfsKaRe" <nthfsskare@ysahoo.in>, "akasdfsh kasdfstla" <akashkatsdfsa@yahsdfsfoo.in>, "Bisdsdfamal Prakaasdsh" <bimsdaalprakash@live.com>,; "milisdfsfnd ansdfasdfnsftwar" <dfdmilifsd.ensfdfcogndfdfatia@gmail.com>').match(re);

//["sdabhikagathara@rediffmail.com", "dsfassdfhsdfarkal@gmail.com", "rfernsdfson@gmail.com", "gyfanamosl@gmail.com", "pidfpinfg@truformdftechnoproducts.com", "nthfsskare@ysahoo.in", "akashkatsdfsa@yahsdfsfoo.in", "bimsdaalprakash@live.com", "dfdmilifsd.ensfdfcogndfdfatia@gmail.com"]

只是对已接受答案的更新。这不适用于电子邮件地址中的“加号”符号。GMAIL 支持 emailaddress+randomtext@gmail.com。

我已经更新为：

return text.match(/([a-zA-Z0-9._+-]+@[a-zA-Z0-9._-]+\.[a-zA-Z0-9._-]+)/gi);

波纹管的功能是RFC2822根据符合Regexr.com

ES5：

var extract = function(value) {
   var reg = /[a-z0-9!#$%&'*+/=?^_`{|}~-]+(?:\.[a-z0-9!#$%&'*+/=?^_`{|}~-]+)*@(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\.)+[a-z0-9](?:[a-z0-9-]*[a-z0-9])?/g;
   return value && value.match(reg);
}

ES6：

const reg = /[a-z0-9!#$%&'*+/=?^_`{|}~-]+(?:\.[a-z0-9!#$%&'*+/=?^_`{|}~-]+)*@(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\.)+[a-z0-9](?:[a-z0-9-]*[a-z0-9])?/g
const extract = value => value && value.match(reg)

Regexr 社区源

function GetEmailsFromString(input) {
  var ret = [];
  var email = /\"([^\"]+)\"\s+\<([^\>]+)\>/g

  var match;
  while (match = email.exec(input))
    ret.push({'name':match[1], 'email':match[2]})

  return ret;
}

var str = '"Name one" <foo@domain.com>, ..., "And so on" <andsoon@gmx.net>'
var emails = GetEmailsFromString(str)

来源